Question

an object moving North with an initial velocity of 14 m s accelerates 5 Ms ^2 for 20 seconds what is the final velocity of the object

Answer 1

the final velocity is 114m/s

`5 = (x - 14)/(20) \\ x = (20 * 5)/(1) + 14 = 100 + 14 \\ 114`


good luck

Answer 2

The final velocity of the object is 114 m/s.

Step-by-step explanation:

It is given that,

Initial velocity of the object, u = 14 m/s

Acceleration of object,
`a=5\ m/s^2`

Time taken, t = 20 s

Let v is the final velocity of the object. It can be calculated using first equation of motion as :

`v=u+at`

`v=14\ m/s+5\ m/s^2* 20\ s`

v = 114 m/s

So, the final velocity of the object is 114 m/s. Hence, this is the required solution.