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Let h(x)=505.5+8e−0.9x . What is h(5) ? rounded to the nearest tenth. any help would be great

User Brian Cray
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2 Answers

4 votes

Answer:

8.9

Explanation:

Let h(x)=505.5+8e−0.9x . What is h(5) ? rounded to the nearest tenth. any help would-example-1
User Dommer
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For this case, the first thing we are going to do is rewrite the function.
We have then:
h (x) = 505.5 + 8 * exp (-0.9 * x)
We evaluate the value of x = 5 in the function.
We have then:
h (5) = 505.5 + 8 * exp (-0.9 * 5)
h (5) = 505.588872
round to the nearest tenth:
h (5) = 505.6
Answer:
the value of h (5) is:
h (5) = 505.6
User Ali Ahsan
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