Question

A sports car moving at constant velocity travels 130 m in 4.9 s . If it then brakes and comes to a stop in 3.8 s , what is the magnitude of its acceleration (assumed constant) in m/s2

Answer 1

the magnitude of the constant acceleration is 6.98 m/s²

Step-by-step explanation:

Given;

distance traveled at a constant velocity, d = 130 m

time of motion, t = 4.9 s

The constant velocity is calculated as;

`v = (d)/(t) \\\\v = (130)/(4.9) \\\\v = 26.53 \ m/s`

The car comes to a stop in 3.8 s.

When the car comes to a complete stop, the final velocity of the car will be zero.

the constant acceleration is calculated as;

v = u + at

0 = u + at

at = -u

a = -u/t

a = (-26.53) / (3.8)

a = -6.98 m/s²

Therefore, the magnitude of the constant acceleration is 6.98 m/s²