Question

A force of 22.04 N is applied tangentially to a wheel of radius 0.340 m and gives rise to an angular acceleration of 1.20 rad/s2. What is the moment of inertia of the wheel

Answer 1

the moment of inertia of the wheel is is 6.245 kg.m²

Step-by-step explanation:

Given;

applied force, f = 22.04 N

radius of the wheel, r = 0.34 m

angular acceleration, a = 1.2 rad/s²

The moment of inertia of the wheel is calculated as;

`I = (\tau)/(\alpha ) \\\\I = (Fr)/(\alpha ) \\\\I = (22.04 \ * \ 0.34 )/(1.2) \\\\I = 6.245 \ kg.m^2`

Therefore, the moment of inertia of the wheel is is 6.245 kg.m²