Question

determine the potential difference between two charged parallel plates that are .10 cm apart and have an electric field strength of 12V/cm

Answer 1

The potential difference between two parallel plates is related to the electric field intensity by

`\Delta V = Ed`
where

`\Delta V` is the potential difference
E is the electric field intensity
d is the distance between the two plates.

In our problem,

`d=0.10 cm`
and

`E=12 V/cm`
so we can calculate the potential difference as

`\Delta V= Ed = (12 V/cm)(0.10 cm)=1.2 V`