Question

3x+6/x^2-x-6+2x/x^2+x-12

place steps to determine the sum of the expressions in the correct order

Answer 1

`(3x+6)/(x^2-x-6) + (2x)/(x^2+x-12)`


`= (3(x+2))/((x + 2)(x - 3)) + (2x)/( (x - 3)(x + 4))`


`= (3)/((x - 3)) + (2x)/( (x -3)(x + 4))`


`= (3(x+4))/((x - 3)(x + 4)) + (2x)/( (x -3 )(x + 4))`


`= (3(x+4) + 2x )/((x - 3)(x + 4))`


`= (3x+12 + 2x )/((x - 3)(x + 4))`


`= (5x+12)/((x - 3)(x + 4))`