Question

Calculate the mass of sodium bromide dihydrate is required to prepare 250 mL of a 0.00600 M solution

Answer 1

Answer: The mass of sodium bromide dihydrate is 0.208 grams

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in ml = 250 ml

moles of
`NaBr.2H_2O` =
`\frac{\text {given mass}}{\text {Molar mass}}=(xg)/(138.92g/mol)`

Now put all the given values in the formula of molality, we get

`0.00600=(x* 1000)/(138.92* 250)`

`x=0.208`

Therefore, the mass of sodium bromide dihydrate is 0.208 grams