Question

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

After adding B2 to both sides of the equation in step 4, what is the constant on the right side of the equation?
 
a.) -32
b.) 112
c.) 160

Answer 1

Please: Use "^" to denote exponentiation: 2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).