Question

Be sure to answer all parts. identify the main group to which x belongs in each ionic compound formula: (a) xf2; (b) mgx; (c) x2so4 xf2 mgx x2so4

Answer 1

(a) Group IIA.

(b) Group VIA.

(c) Group IA.

Step-by-step explanation:

Hello,

To solve this problem, one remembers that the subscripts are related with both the cation's and anion's oxidation states exchanging which are also related with the group they belong, thus:

(a) For
`XF_2` since the fluoride anion has 2 as the subscript and -1 as its charge, X should belong to group IIA because X has 1 as its subscript.

(b) For
`MgX` since the magnesium cation has 1 as the subscript and it belongs to group IIA, it means that it has +2 and the anion has -2 as the charges, thus, X should belong to group VIA for the nonmetals that have such oxidation state.

(c) For
`X_2SO_4` since the sulfate anion has 1 as the subscript, and X has two, X should belong to group IA.

Best regards.

Answer 2

Part (a):
For the compound XF₂, X must be a metal. As fluorine is monovalent and there are two fluorine atoms, so the valency of X must be two.
Therefore, X belongs to group 2

Part (b):
For the compound MgX, X must be non-metal. As magnesium is divalent and there is one magnesium atom, so the valency of X must be two.
Therefore, X belongs to group 16

Part (c):
For the compound X₂SO₄, X must be a hydrogen or metal. As sulfate is divalent and there is two X atoms, so the valency of X must be one.
Therefore, X belongs to group 1