Answer:
5.90x10²² atoms of gold are present in the cube
Step-by-step explanation:
First, we must find the volume of the cube in cm³. With density we can find the mass of the gold and the moles using its molar mass. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:
Volume in cm³:
(10.0mm)³ = 1000mm³
1mm³ = 0.001cm³
1000mm³ * (0.001cm³ / 1mm³) = 1cm³
Mass gold:
1cm³ * (19.3g/cm³) = 19.3g Gold
Moles Gold:
19.3g * (1mol / 197.0g) = 0.0980 moles Gold
Atoms gold:
0.0980 moles Gold * (6.022x10²³ atoms / mol) =
5.90x10²² atoms of gold are present in the cube