Answer:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collected
Step-by-step explanation:
A solution 5% of potassium chloride means that there are 5g of KCl per 100g of solution.
When all the solution is evaporated, the solute KCl will be collected as a solid.
In 150g of solution there are:
150g * (5.00gKCl / 100g solution) = 7.50g of KCl are present in 150g of solution.
That means:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collected