Answer:
Angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;
∅₁ = 0.8439°
∅₂ = 0.1688°
∅₃ = 0.2533°
Step-by-step explanation:
Given that;
wavelength λ = 560 nm = 560 × 10⁻⁹
Separation between slits d = 0.380 mm = 0.00038
n = first three orders = 1st order, 2nd order and 3rd oder.
we know that for constructive interference;
λn = dsin∅
sin∅ = λn/d
∅ = sin⁻¹ ( λn/d )
where λ is wavelength, ∅ is the angle, d is the distance between slits, n is the order of constructive interference.
now;
-First order; n = 1
∅₁ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(1) /0.00038 )
∅₁ = sin⁻¹( 0.001473) = 0.8439°
-2nd order; n = 2
∅₂ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(2) /0.00038 ) =
∅₂ = sin⁻¹( 0.002947) = 0.1688°
-3rd order; n = 3
∅₃ = sin⁻¹(λn/d) = sin⁻¹( (560 × 10⁻⁹)×(3) /0.00038 ) =
∅₃ = sin⁻¹( 0.004421) = 0.2533°
Therefore, angles corresponding to the locations of the first three orders of bright fringes away from the central bright fringe are;
∅₁ = 0.8439°
∅₂ = 0.1688°
∅₃ = 0.2533°