Answer:
Step-by-step explanation:
The following code is written in Python and is a full Two player tic tac toe game on a 3x3 grid that is represented by numbers per square.
# Making all of the main methods of the game
board = [0,1,2,
3,4,5,
6,7,8]
win_con = [[0,1,2],[3,4,5],[6,7,8],
[0,3,6],[1,4,7],[2,5,8],
[0,4,8],[2,4,6]] # possible 3-in-a-rows
def show():
print(board[0],'|',board[1],'|',board[2])
print('----------')
print(board[3],'|',board[4],'|',board[5])
print('----------')
print(board[6],'|',board[7],'|',board[8])
def x_move(i):
if board[i] == 'X' or board[i] == 'O':
return print('Already taken!')
else:
del board[i]
board.insert(i,'X')
def o_move(i):
if board[i] == 'X' or board[i] == 'O':
return print('Already taken!')
else:
del board[i]
board.insert(i,'O')
# Creating the main loop of the game
while True:
turn_num = 1
board = [0,1,2,3,4,5,6,7,8]
print('Welcome to Tic-Tac-Toe!')
print('AI not implemented yet.')
while True:
for list in win_con: #check for victor
xnum = 0
onum = 0
for num in list:
if board[num] == 'X':
xnum += 1
elif board[num] == 'O':
onum += 1
else:
pass
if xnum == 3 or onum == 3:
break
if xnum == 3 or onum == 3: # break loops
break
if turn_num > 9: # Check if there are any more moves available
break
show()
if turn_num % 2 == 1:
print('X\'s turn.')
else:
print('O\'s turn.')
move = int(input('Choose a space. '))
if turn_num % 2 == 1:
x_move(move)
else:
o_move(move)
turn_num += 1
if xnum == 3: #If game ends
print('X Won!')
elif onum == 3:
print('O Won!')
else:
print('Draw!')
play_again = input('Play again? Y or N ')
if play_again == 'Y' or play_again == 'y':
continue
else:
break