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Find the equation of the circle that has diameter endpoints of (2, 2) and (20, 26). A. (x - 8)2 + (y - 11)2 = 324 B. (x - 11)2 + (y - 14)2 = 144 C. (x - 11)2 + (y - 14)2 = 225 D. (x - 8)2 + (y - 11)2 =
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May 21, 2019
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Find the equation of the circle that has diameter endpoints of (2, 2) and (20, 26). A. (x - 8)2 + (y - 11)2 = 324 B. (x - 11)2 + (y - 14)2 = 144 C. (x - 11)2 + (y - 14)2 = 225 D. (x - 8)2 + (y - 11)2 = 15
Mathematics
middle-school
Gbaor
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The midpoint of (2,2) and (20,26) is (11,14).
This means that k and h in the equation will be 11 and 4.
To find the radius, divide the diameter by 2.
The diameter is 18. 18/2 = 9.
The equation will be (x - 11)^2 + (y - 14)^2 = 81
Bocaxica
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May 26, 2019
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