Question

one gram of gold has 3.06*10^21 atoms, and each gold atom has 79 electrons. How many electrons are contained in 8.00 g of gold? The elemental charge is 1.6*10^-19 C. Answer in units of electrons

Answer 1

First, let's calculate how many atoms are contained in 8.00 g of gold. To do that, we should multiply the number of atoms in one gram by the mass of the gold:

`N_a = (8.00 g) (3.06 \cdot 10^(21) atoms/g)=2.45 \cdot 10^(22) atoms`

Then we know that each atom contains 79 electrons, so in order to get the total number of electrons, we should multiply the total number of atoms by the number of electrons per atom:

`N_e = (2.45 \cdot 10^(22) atom)(79 e/atom)=1.94 \cdot 10^(24) e`
and this is the total number of electrons in 8.00 g of gold.