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The table represents the start of the division of -2x^3+11x^2-23x+20 by x^2-3x+4

2 Answers

3 votes
Not sure what the question is, but the quotient is -2x+5.

We first look for the number of times x² goes into -2x³. It goes in -2x times. This goes over -23x in the box. Multiply back by the divisor, and the product we write under the dividend in the box is

-2x³+6x²-8x

We now have this subtraction:
-2x³+11x²-23x
-(2x³+ 6x²- 8x)

Which gives us
5x²-15x

Bring down the 20 from the dividend and we have
5x²-15x+20

Now we see how many times x² will go into 5x². It goes 5 times, so we write +5 beside our -2x in the quotient. Multiply 5 by the divisor, and we have the following to write under the next line in our process:
5x²-15x+20

When we subtract this from the previous line, we have 0 remainder.
User Remko Duursma
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9.0k points
5 votes

Answer:

the answer is D.20

Explanation:

i guessed on the test and got it right

User Igor Escobar
by
8.0k points

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