Question

What’s the answer for this question??

Answer 1

The area of the regular pentagon is equal of 5 times the area of the triangle.

The formula of an area of a triangle:

`A_\triangle=(bh)/(2)`

We have:

`b=11.8\ in\\h=8.1\ in`

Substitute

`A_\triangle=(11.8\cdot8.1)/(2)=47.79\ in^2`

The area of the regular pentagon:

`A=5\cdot47.79=238.95\ in^2`