Question

A spinner is divided into sections of equal size, of which some are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 20%. The probability of the arrow landing on a section colored blue is 10%. What is the probability of the arrow landing on a section colored green.

10%
20%
30%
70%
Plz help

Answer 1

So, the full percentage would be 100%.
First, add the two percentages of red and green that has been taken up.
10+20=30
So, subtract that 30% from 100%.
100-30=70
So, the probability of the arrow landing on the green section is 70%.

Answer 2

70%

Explanation:

The total probability theorem allows us to calculate the probability of an event from conditioned probabilities. The events have to form a complete system, that is, they contemplate all possibilities (the sum of their probabilities must be 100%).

Be the events,

A = The arrow falls in the color red

B = The arrow falls in the color blue

C = The arrow falls in the color green

The odds given are as follows:

P (A) = 20%

P (B) = 10%

P (C) =?

According to the total probability theorem,

P (A) + P (B) + P (C) = 100%

Isolating P (C), we have

P (C) = 100% - P (A) - P (B)

Substituting the variables for the corresponding data,

P (C) = 100% - 20% - 10%

P (C) = 70%

Hope this helps!