Question

A centrifuge accelerates uniformly from rest to 13000 rpm in 220 s . through how many revolutions did it turn in this time?

Answer 1

We have the following angular velocity:
w = 13000 rpm
We are going to convert to revolutions per second.
We have then:
w = 13000 * (1/60)
w = 216.6666667 rev / sec
We now multiply the angular velocity by time:
(216.6666667) * (220)
= 47666.66667 rev
Rounding:
47667 rev
Answer:
it did turn about 47667 rev in this time

Answer 2

23833.33

Explanation:

The first step is to find the average velocity. To do this you simply divide by two.

13000rpm/2=6500rpm

To make it easier to work with you will convert it from rpm to rps

6500rpm/60=108.33rps

Then you multiply the revolutions per second by the number of seconds to find the amount of revolutions.

108.33rps*220sec=23833.33 revolutions