Question

A rocket launcher makes an angle of 53.1 from the ground. It launches a rocket with an initial speed of 20.8m/s

How far is it horizontally, in meters, after 1.43s QUICKLy

Answer 1

Explanation:

Givens:

`s _(x) = 20.8 \cos(53.1)`

`t = 1.43`

Since speed in the x direction is constant, we can use this equation

`h = s _(x) * t`

where h is the distance horizontally

`h = 20.8 \cos(53.1) * 1.43`

`h = 17.85889 \: m`

round is needed