Question

Wart remover is made of 9M of salicylic acid. If i pour 200 mL of 9M of salicylic acid into a graduated cylinder and fill it up to the 1L mark with water, what is my new molarity of salicylic acid?

Answer 1

To find the new molarity of salicylic acid after dilution, use the formula M1V1 = M2V2. In this case, the new molarity is 1.8M.

Step-by-step explanation:

To find the new molarity of salicylic acid after dilution, we can use the formula:

M1V1 = M2V2

Where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume, respectively.

In this case, the initial molarity (M1) is 9M, the initial volume (V1) is 200 mL, and the final volume (V2) is 1L (1000 mL).

Plugging in the values, we have:

9M * 200 mL = M2 * 1000 mL

Solving for M2:

M2 = (9M * 200 mL) / 1000 mL

M2 = 1.8M

Therefore, the new molarity of salicylic acid after dilution is 1.8M.

Answer 2

Hello!

To solve this problem we will use the dilution reaction, assuming that the number of moles of Salicylic Acid (SA) taken from the first solution will be the same as the total moles in the second solution and clear for the concentration of salicylic acid in the second solution:


`molesSA_1=molesSA_2 \\ \\ cSA_1*VSA_1=cSA_2*VSA_2 \\ \\ cSA_2= (cSA_1*VSA_1)/(VSA_2) = (200 mL * 9M)/(1000 mL)=1,8 M`

So, the concentration of Salicylic Acid in the second solution would be 1,8M

Have a nice day!