the correct question is
ABCD is a rectangle. what is the length of the diagonals if AC= 3y/5 and BD= 3(y-4)
see the figure attached to better understand the problem
we know that
Given AC and BD are diagonals. In a rectangle diagonals are equal.
Therefore AC = BD=> 3y/5 = 3y - 4=> 3y = 5(3y - 4)=> 3y = 15y - 20=> 12y = 20=> y = 20/12 = 5/3Therefore AC = 3y/5= 3(5/3)/5= 1 unitsand BD = 3y - 4= 3(5/3) - 4= 5 - 4= 1 unitsthe answer is
The length of each diagonal is 1 units