Question

A normal human heart, beating about once per second, creates a maximum 4.00-mv potential across 0.250 m of a person\'s chest, producing a 1.00-hz electromagnetic wave. what is the maximum electric field strength produced?

Answer 1

Explanation :

It is given that,

Potential,
`V=4\ mV=4* 10^(-3)\ V`

This potential across the person's chest is at a distance of 0.250 m

Frequency of electromagnetic wave, f = 1 Hz

We know that the electric field is defined as :

`E=(V)/(d)`

V is the potential

d is the distance

`E=(4* 10^(-3)\ V)/(0.250\ m)`

`V=0.016\ V/m`

So, the maximum electric strength is 0.016 V/m.

Hence, this is the required solution.

Answer 2

If we have a 4mV potential accross 0.250 m

We apply

E = V/m

E = 4mV/0.25m = 0.016 V/m (Max Electric field)