Question

How many moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in H2O?

Answer 1

Step-by-step explanation:

Molarity is defined as number of moles divided by volume in liter.

Mathematically, Molarity =
`(no. of moles)/(Volume in liter)`

Since, it is known that 1 L equals 1000 ml so 65.0 mL equals 0.065 L.

Therefore, it is given that volume is 0.065 L and molarity is 2.20 M. Hence, calculate number of moles as follows.

Molarity =
`(no. of moles)/(Volume in liter)`

Number of moles =
`Molarity * Volume in liter`

=
`2.20 M * 0.065 L`

= 0.143 mol

Thus, we can conclude that there are 0.143 moles NaOH are contained in 65.0 mL of a 2.20 M solution of NaOH in
`H_2O`.

Answer 2

The number of moles of NaOh that are contained in 65ml of 2.20M solution NaOh in H2o is calculated using the below formula


moles = molarity x volume /1000

that is 65 x2.20 /1000= 0.143 moles