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93.0 mL of O2 gas is collected over water at 0.930 atm and 10.0C what would be the volume of this dry gas at STP

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The volume of the dry gas at stp is calculated as follows

calculate the number on moles by use of PV =nRT where n is the number of moles

n is therefore = Pv/RT
P = 0.930 atm
R(gas contant= 0.0821 L.atm/k.mol
V= 93ml to liters = 93/1000= 0.093L
T= 10 + 273.15 = 283.15k

n= (0.930 x0.093) /(0.0821 x283.15) = 3. 72 x10^-3 moles

At STp 1 mole = 22.4L
what about 3.72 x10^-3 moles

by cross multiplication

volume = (3.72 x10^-3)mole x 22.4L/ 1 moles = 0.083 L or 83.3 Ml
User Manjurul Ahsan
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