The sample space is 6 different colors1) P(Red) =1/6 P(Blue) = 1/6 P(Red AND Blue) =P(Red ∩ Blue) (1/6) x (1/6) = 1/362)
P(of Blue) =1/2 , P)Red) =1/2 ,
P(getting 5) =1/6, P(getting 1,2 or 3)=3/6=1/2
P(Blue AND 5) =1/2 x 1/6 = 1/12
P(Red AND 1 OR 2 OR 3) = 1/2 x 1/2 = 1/4
Probability of Event A AND Event B = 1/12 x 1/4 =1/48 =0.021 (I don't see it on your paper)