Question

What are the spectator ions in the solution after the precipitation of an insoluble sulfate compound from AgNO3(aq) and K2SO4(aq)?

Answer 1

Answer: The spectator ions in the solution will be
`K^+\text{ and }NO_3^-`

Explanation: Spectator ions are the ions which are present in the same form on both the sides of a chemical reaction.

For a given Chemical reaction:

`2AgNO_3(aq.)+K_2SO_4(aq.)\rightarrow Ag_2SO_4(s)+2KNO_3(aq.)`

precipitate formed is silver sulfate.

The Ionic equation for the above chemical reaction is:

`2Ag^+(aq.)+2NO_3^-(aq.)+2K^+(aq.)+SO_4^(2-)(aq.)\rightarrow Ag_2SO_4(s)+2K^+(aq.)+2NO_3^-(aq.)`

As,
`K^+\text{ and }NO_3^-` do not precipitate and hence, are considered as the spectator ions.

Net Ionic equation becomes:

`2Ag^+(aq.)+SO_4^(2-)(aq.)\rightarrow Ag_2SO_4(s)`

Answer 2

the chemical equation
2AgNO3 (aq) + K2SO4 (aq) = Ag2SO4 (s) + 2KNO3(aq)

ionic equation
2Ag^+(aq) + 2 NO3^-(aq) + 2k^+(aq) + SO4^ 2-(aq) = Ag2SO4(s) +2K ^+(aq) + 2NO3 ^-(aq)

the spectator ion is therefore = 2k^+ and 2NO3^-

therefore net ionic equation = 2Ag^+(aq) + SO4^2- = Ag2So4(s)