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A sample of inert gas has an initial volume of 5.6 L at a pressure of 735 mm Hg. If the volume of gas is increased to 9.4 L, what is its pressure?

User Cazman
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2 Answers

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Answer:

p2= 735mmhg x 5.6 L/ 9.4l= 437.87 mmhg

Step-by-step explanation:

3 votes
The pressure of inert gas if the volume of gas is increased to 9.4l is calculated using P1v1= P2 V2 formula where p is for pressure while is for volume

P1 = 735 mm hg
v1 = 5.6 L
V2= 9.4 L
P2= ?

from the formula above P2 = P1V1/ V2

p2= 735mmhg x5.6 L/ 9.4l= 437.87 mmhg
User Csjohnst
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