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In AABC, MZA = 16°, mZB = 49°, and
a = 4. Find c to the nearest tenth.

In AABC, MZA = 16°, mZB = 49°, and a = 4. Find c to the nearest tenth.-example-1
User LexLythius
by
6.7k points

1 Answer

6 votes

Answer:

(c) 13.2

Explanation:

The sum of angles in a triangle is 180°, so angle C is ...

C = 180° -A -B

C = 180° -16° -49° = 115°

The measure of side c can be found from the Law of Sines:

c/sin(C) = a/sin(A)

c = a·sin(C)/sin(A) = 4·sin(115°)/sin(16°)

c ≈ 13.2

In AABC, MZA = 16°, mZB = 49°, and a = 4. Find c to the nearest tenth.-example-1
User Parthi
by
7.0k points
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