Question

Like all equilibrium constants, the value of kw depends on temperature. at body temperature (37∘c), kw=2.4⋅10−14. part a what is the [h3o+] in pure water at body temperature?

Answer 1

first, we have to know that we can put [H+] instead of [H3O+]

so, according to the reaction equation:

by using ICE table:

H2O ↔ H+ + OH-

initial 0 0

change +X +X

Equ X X

when Kw = [H+] [OH-]

and when we have Kw = 2.4 x 10^-14

and when [H+] = [OH-] = X

∴ 2.4 x 10^-14 = X^2

∴ X = √(2.4 x 10^-14)

= 1.55 x 10^-7

∴[H+] = 1.55 x 10^-7