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How do you simplify square root of 5yv^2 sqaure root of 15y^2v^9

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\sqrt{5yv^(2) } = v √(5y)

\sqrt{ {15y}^(2)2 {v}^(9) } \\ = yv^(4) √(15 * 2v) \\ = y {v}^(4) √(30v)
Hope this helps. - M
User Gyosifov
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