Question

How much charge does a 9.0 v battery transfer from the negative to the positive terminal while doing 39 j of work?

Answer 1

The work done by the battery is equal to the charge transferred during the process times the potential difference between the two terminals of the battery:

`W=q \Delta V`
where q is the charge and
`\Delta V` is the potential difference.

In our problem, the work done is W=39 J while the potential difference of the battery is
`\Delta V = 9.0 V`, so we can find the charge transferred by the battery:

`q= (W)/(\Delta V)= (39 J)/(9.0 V)=4.33 C`