Question

A rope vibrates every 0.5 s. what is the frequency of the waves?

Answer 1

F = 1/t
F = 1/0.5
F = 2Hz

Answer is 2Hz

Answer 2

The rope vibrates every 0.5 s: it means that its period is

`T=0.5 s`

The frequency of an oscillation is equal to the reciprocal of the period:

`f=(1)/(T)`

Therefore, if we substitute T=0.5 s in the formula, we get:

`f=(1)/(0.5 s)=2 Hz`