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The distance from town x to town y is 200 km. The distance from town x to town. Z is is 135km. Looking from town y, town x & and town Z are Seperated by an angle of 42°. a) Sketch a possible diagram for this situation. b) Calculate the possible distance from town y to town Z .​

User TechnoCorner
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1 Answer

17 votes
17 votes

Answer:

a) see attached

b) 131 km or 166 km

Explanation:

a)

Two sides and an angle are given for the triangle. The given angle is opposite the shortest of the given sides, so there will be two possible solutions. These are shown in the attachment.

__

b)

The Law of Sines is used to calculate the unknown side length. That law tells you ...

x/sin(X) = y/sin(Y) = z/sin(Z) . . . . . where y = 135, z = 200, Y = 42°

In order to find side x, we need to know angle X. We find that from angle Z and the fact that the sum of angles in the triangle is 180°.

Z = arcsin(z/y·sin(Y)) = arcsin(200/135·sin(42°)) ≈ arcsin(0.991305)

Z ≈ 82.44° or 97.56° . . . . the principal value or its supplement

Then the angle X is ...

180° -42° -82.44° = 55.56°

or

180° -42° -97.56° = 40.44°

Side x is then either of ...

x = y·sin(X)/sin(Y) = 135/sin(42°)·sin({40.44°, 55.56°})

x ≈ {130.86, 166.39} . . . km

Possible distances from Y to Z are about 131 km or 166 km.

The distance from town x to town y is 200 km. The distance from town x to town. Z-example-1
User Wenda
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