Question

Which quadratic equation is equivalent to (x+2)^2+5(x+2)-6=0

Answer 1

x^2 + 9x + 8 = 0

You can get this by multiplying and foiling, then simplifying.

Answer 2

`x^2+11x+24 =0`

Explanation:

`(x+2)^2+5(x+2)-6=0`

Substitute

`x+2 =y`

`y^2+5y-6=0\\(y+6)(y-1)=0\\y=-6,1`

Now replace y by x values

`x+2=-6\\x=-8\\x+2=-1\\x=-3`

Roots are -3 and -8

The equivalent equation would be

`(x+3)(x+8) =0\\x^2+11x+24 =0`