61.5k views
2 votes

2a - 3 \geqslant 11

User Jinhong
by
7.6k points

1 Answer

0 votes

Answer:


\large\boxed{a\geq7\to a\in[7,\ \infty)}

Explanation:


2a-3\geq11\qquad\text{add 3 to both sides}\\\\2a-3+3\geq11+3\\\\2a\geq14\qquad\text{divide both sides by 2}\\\\(2a)/(2)\geq(14)/(2)\\\\a\geq7

User GaryJ
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories