Find the horizontal or oblique asymptote of f(x) = negative 3 x squared plus 7 x plus 1, all over x minus 2

asked May 4, 2019 127k views

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When you perform the indicated division, you get

(-3x^2+7x+1)/(x-2)=-3x+1+(3)/(x-2)

The "quotient" part of this result is the oblique asymptote:
y = -3x +1

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