36.2k views
4 votes
How many solution does x^2=4x-5 have

1 Answer

4 votes
x^2-4x+5=0
D= b²-4ac=16-4*5*1=16-20=-4
so no real solutions, because D<0
and it is going to be only 2 imaginary solutions
User Matthew Baker
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories