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What is the vertex of the graph of this equation y= -4x^2-16x-12

User JoeFox
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1 Answer

4 votes
One way to locate the vertex is to obtain the coefficients a, b and c from the quadratic and then calculate
-(-16)
x = -b / (2a). Here, x = ---------- = -2
2(-4)

Next, evaluate y at x = -2: y = -4(-2)^2 - 16(-2) - 12 = -16 + 32 - 12
y = 4

the vertex is at (-2,4).