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Which is the inverse of the function f(x) = 4x2?

User BinaryLV
by
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1 Answer

2 votes

Answer:


f^(-1)(x)=(1)/(2)√(x)

Explanation:

To find the inverse of a function, change the f(x) to a y, switch the places of x and y, then solve for the new y:


f(x)=4x^2 becomes
y=4x^2

Now switch the places of x and y:


x=4y^2 and solve for the new y:


(1)/(4)x=y^2

Take the square root of both sides to "undo" the square on the y:


\sqrt{(1)/(4)x } =y

and the square root of 1/4 is 1/2, so we have in the end:


y=(1)/(2)√(x)

Now you can put it back into inverse function notation since that is, after all, an inverse function:


f^(-1)(x)=(1)/(2)√(x)

User Thilanka
by
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