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1 vote
Determine in which direction the parabola opens y=-3x^2+5x+11
up down
left
right

2 Answers

3 votes

Answer:

The answer is D

Explanation:

User Carleen
by
8.4k points
4 votes
we have that
y=-3x²+5x+11

we know that
the equation of the parabola in standard form can be expressed in one of the following two ways
y=ax²+bx+c
the parabola opens up if a is positive and opens down if a is negative
and
x=ay
²+by+c
the parabola opens right if a is positive and opens left if a is negative

in this problem
the equation is of the form
y=ax²+bx+c
a=-3
so
the parabola opens down

using a graph tool
see the attached figure
the vertex of a parabola is a maximum

the answer is
the parabola opens down
Determine in which direction the parabola opens y=-3x^2+5x+11 up down left right-example-1
User Alex Couper
by
8.2k points

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