Question

In part a, we saw that the theoretical yield of aluminum oxide is 0.700 mol . calculate the percent yield if the actual yield of aluminum oxide is 0.329 mol .

Answer 1

The % yield is calculated as follows

% yield = actual yield/ theoretical yield x100

theoretical yield = theoretical moles x molar mass
= 0.700 mole x 101.96 g/mol = 71.372 grams

actual mass = actual moles x molar mass
= 0.329 mol x 101.96 = 33.545 grams

% yield is therefore= 33.545/71.372 x100= 47%