Question

How many milliliters of 1.0m agno3 are needes to provide 169.9 g of agno3?

Answer 1

The molar mass of silver nitrate is 169.87 g/mol
Therefore the number of moles in 169.9 g will be;
= 169.9/169.87
= 1 mole
Therefore; since the molarity is 1.0 M
then the volume= 1/1 =1 liter which is equivalent to 1000ml
Thus, the answer is 1000 ml

Answer 2

The number of Ml of 1.0 AgNo3 needed to provide 169.9 0f AgNO3 is calculated as follows

find the moles of AgNo3

= mass/molar mass = 169.9/169.87 = 1 mole

volume in Ml = moles/ molarity x1000

= 1/1 x1000= 1000 ml