Question

The heat (or enthalpy) of fusion for ice is 0.334 kj/g.

how many kilojoules of energy (q) are required to melt 22.4 g of ice at its melting point (0°c)?

Answer 1

According to this formula:

Q = ΔH fusion * mass (g)

when we have:

ΔH fusion (the heat (or enthalpy) of fusion = 0.334 kJ/g

and mass of ice = 22.4 g

so by substitution, we can get the energy (Q) required to melt this mass of ice:

∴ Q = 0.334KJ/g * 22.4 g

= 7.48 KJ

∴ the energy required to melt 22.4 g of ice is = 7.48 KJ