Question

How many grams of fe2o3 are there in 0.500 mol of fe2o3?

Answer 1

79.844 g.

Step-by-step explanation:

First we are going to calculate the molar mass of
`Fe_(2)O_(3)`

The molar mass of Fe is
`55.845(g)/(mol)` this means that 1 mol of Fe has a mass of 55.845 g.

The molar mass of O is
`15.999(g)/(mol)` this means that 1 mol of O has a mass of 15.999 g

To calculate the molar mass of
`Fe_(2)O_(3)` we calculate the following number :

`2.(55.845(g)/(mol))+3.(15.999(g)/(mol))=159.687(g)/(mol)`

This means that 1 mol of
`Fe_(2)O_(3)` has a mass of 159.687 g.

Finally, in 0.500 mol of
`Fe_(2)O_(3)` we have

`159.687(g)/(mol).(0.500mol)=79.844g`

There are 79.844 g of
`Fe_(2)O_(3)` in 0.500 mol of
`Fe_(2)O_(3)`

Answer 2

Molar Mass of Fe₂O₃ = 159.69 g/mol

As we know,
Moles = Mass / M.mass
Solving for Mass,
Mass = Moles × M.mass
Putting Values,
Mass = 0.50 mol ×159.69 g/mol

Mass = 79.84 g