Question

How to graph (-6, -2) - (8, -2)

Answer 1

the function that unites these two points is a constant line on y=-2

Explanation:

P1=(-6,-2)

P2=(8,-2)

y=mx+b

In order to calculate m (the pendant):

m=
`(-2-(-2))/(8-(-6)) \\`

m=0

Then, you need to replace y & x with the values of one of the points:

-2=0*(-6)+b

-2=b

Finally, replace m & b in y=mx+b:

y=-2