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To approach the runway, a pilot of a small plane must begin a 10 degree descent from a height of 1983 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?

User Shabbir
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1 Answer

5 votes
Sin10=1790/d

D=1983/(sin 10)

D=11665 feet

Since there is 5,280 feet in one mile we have

11665/5280=2.2 miles
User Tiasha
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