Question

Which equation has the solutions x=-3 -+ square root of 3i/2?

2x2 + 6x + 9 = 0
x2 + 3x + 12 = 0
x2 + 3x + 3 = 0
2x2 + 6x + 3 = 0

Answer 1

A.

You can get this by using the quadratic function.

Answer 2

`x^2+3x+3=0`

Explanation:

Given :
`x=(-3 \pm √(3)i)/(2)`

To Find :Which equation has the solutions
`x=(-3 \pm √(3)i)/(2)`

Solution:

`(x-3 - √(3i))/(2) * (x-3+ √(3i))/(2)=0`

`x^2-(3-√(3)i)/(2)x-(3+√(3)i)/(2)x+(9-3i^2)/(4)=0`

`x^2-(-6x)/(2)+(9-3(-1))/(4)=0`

`x^2+3x+3=0`

So, equation has the solutions
`x=(-3 \pm √(3)i)/(2)` is
`x^2+3x+3=0`