50.2k views
5 votes
Which of the following is a valid exclusion for the algebraic fraction:

(27a^3-1) / (9a^2-6a+1)?

a. a≠0
b. a≠1
c. a≠1/3
d. a≠3

User Merissa
by
6.2k points

2 Answers

1 vote

Answer:

a ≠ 1/3

Thanks to the guy above, I got the answer right! :)

User Richard Pennington
by
6.5k points
6 votes
We have the following expression:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
Rewriting we have:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
(27a ^ 3-1) / ((3a-1) * (3a-1))
We exclude the values that make the denominator zero:
3a-1 = 0
a = 1/3
Answer:
a valid exclusion for the algebraic fraction is:
c. a ≠ 1/3
User ExoRift
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.