Question

The interest rate r required to increase investment p to amount a in t years is found using the formula r=(a/p)^1-t - 1. Find the interest rate r when p =2500, a =3600, and t =2.

Answer 1

I believe the answer is 20% (sorry if i am wrong)

Answer 2

The interest rate would be 20%.

The formula is derived from the compound interest formula


`A=p(1+r)^t`.

We want to isolate r in this equation to rewrite the formula. The first thing we would cancel, outside parentheses, would be p; divide both sides by p and we have


`(A)/(p)=(1+r)^t`

We want to cancel the exponent, t, next. We can raise a power to its reciprocal to undo it; for example, raising a squared amount to the 1/2 power will undo the exponent. We will raise both sides of this to the 1/t power:


`((A)/(p))^{(1)/(t)}=1+r`

Now we cancel the 1 by subtracting, giving us


`((A)/(p))^{(1)/(t)}-1=r`

Using this formula, we plug in 3600 for A, 2500 for p and 2 for t: